Problem D8:
A circular object of mass m and radius R starts out spinning in the air just above the floor. While
spinning with an initial angular velocity of ω_{0} = n_{1}/R,
it is gently placed on the floor. There is friction between the object and the
floor causing it to move to the right while the angular velocity decreases.
Finally, the object rolls without slipping attaining a final speed of
n_{3}. If the rotational inertia I divided by mR_{2} of the
object equals I/(mR^{2})=2/n_{2} , what is n_{3}?
Note that n_{1} and n_{3} have the same units of speed, and
n_{2} is unitless. For a ring, n_{2} = 2; for a disk,
n_{2} = 4; and for a sphere, n_{2} = 5.

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